Accueil > Educatif > Faire des mots croisés
Faire des mots croisés
Publié le 3 décembre 2014, dernière mise-à-jour le 24 janvier 2019, 0 visites, visites totales.
Manip
- 1 télécharger le programme
, l’ouvrir et enregistrer/extraire le fichier crosswords.py
- 1bis créer un fichier machin.py n’importe où, copier coller le code d’en bas, enregistrer
- 2. ouvrir le fichier avec python ( click droite , ouvrir avec ... )
- 2bis. ouvrir un terminal, taper python machin.py
- 3 une fois fini un fichier s’ouvre
Vidéos de la manipulation :
changer les mots
On peut voir dans le code les lignes suivantes
word_list = ['saffron', 'The dried, orange yellow plant used to as dye and as a cooking spice.'], \
['pumpernickel', '
...............................................................................
ve.'], \
['snicker', 'A snide, slightly stifled laugh.']
Chaque ligne contient :
un crochet,une guillemet ,le mot, une guillemet, une virgule, une guillemet, la description, une guillemet, un crochet, une virgule, un anti slash
La derniere ligne contient la meme chose sans une virgule, un anti slash à la fin
On peut aussi remplacer toutes les lignes de word_list par ;
def supprime_accent(ligne):
accent = ['é', 'è', 'ê', 'à', 'ù', 'û', 'ç', 'ô', 'î', 'ï', 'â']
sans_accent = ['e', 'e', 'e', 'a', 'u', 'u', 'c', 'o', 'i', 'i', 'a']
for i in range(len(accent)):
ligne = ligne.replace(accent[i], sans_accent[i])
return ligne
word_list=[]
f=open('/usr/share/dict/words','r')#140000 mots
nb=0
for line in f:
if random.random()>0.999:
texte=supprime_accent(line)#.translate('aaceeeeiouu', 'àâçêééèîôûù')#
word_list.append([texte,texte])
nb+=1
print(line)
f.close()
Le programme tire au hasard des mots dans le dictionnaire /usr/share/dict/words
.
On peut aussi utiliser son propre fichier texte comprenant un mot par ligne et mettre son nom à la place de /usr/share/dict/words
dans le code précédent.
Fichier à copier coller
# -*- coding: utf-8 -*-
from __future__ import print_function
import random, re, time, string,os
from copy import copy as duplicate
# optional, speeds up by a factor of 4
class Crossword(object):
def __init__(self, cols, rows, empty = '-', maxloops = 2000, available_words=[]):
self.cols = cols
self.rows = rows
self.empty = empty
self.maxloops = maxloops
self.available_words = available_words
self.randomize_word_list()
self.current_word_list = []
self.debug = 0
self.clear_grid()
def clear_grid(self): # initialize grid and fill with empty character
self.grid = []
for i in range(self.rows):
ea_row = []
for j in range(self.cols):
ea_row.append(self.empty)
self.grid.append(ea_row)
def randomize_word_list(self): # also resets words and sorts by length
temp_list = []
for word in self.available_words:
if isinstance(word, Word):
temp_list.append(Word(word.word, word.clue))
else:
temp_list.append(Word(word[0], word[1]))
random.shuffle(temp_list) # randomize word list
temp_list.sort(key=lambda i: len(i.word), reverse=True) # sort by length
self.available_words = temp_list
def compute_crossword(self, time_permitted = 1.00, spins=2):
time_permitted = float(time_permitted)
count = 0
copy = Crossword(self.cols, self.rows, self.empty, self.maxloops, self.available_words)
start_full = float(time.time())
while (float(time.time()) - start_full) < time_permitted or count == 0: # only run for x seconds
self.debug += 1
copy.current_word_list = []
copy.clear_grid()
copy.randomize_word_list()
x = 0
while x < spins: # spins; 2 seems to be plenty
for word in copy.available_words:
if word not in copy.current_word_list:
copy.fit_and_add(word)
x += 1
#print copy.solution()
#print len(copy.current_word_list), len(self.current_word_list), self.debug
# buffer the best crossword by comparing placed words
if len(copy.current_word_list) > len(self.current_word_list):
self.current_word_list = copy.current_word_list
self.grid = copy.grid
count += 1
return
def suggest_coord(self, word):
count = 0
coordlist = []
glc = -1
for given_letter in word.word: # cycle through letters in word
glc += 1
rowc = 0
for row in self.grid: # cycle through rows
rowc += 1
colc = 0
for cell in row: # cycle through letters in rows
colc += 1
if given_letter == cell: # check match letter in word to letters in row
try: # suggest vertical placement
if rowc - glc > 0: # make sure we're not suggesting a starting point off the grid
if ((rowc - glc) + word.length) <= self.rows: # make sure word doesn't go off of grid
coordlist.append([colc, rowc - glc, 1, colc + (rowc - glc), 0])
except: pass
try: # suggest horizontal placement
if colc - glc > 0: # make sure we're not suggesting a starting point off the grid
if ((colc - glc) + word.length) <= self.cols: # make sure word doesn't go off of grid
coordlist.append([colc - glc, rowc, 0, rowc + (colc - glc), 0])
except: pass
# example: coordlist[0] = [col, row, vertical, col + row, score]
#print word.word
#print coordlist
new_coordlist = self.sort_coordlist(coordlist, word)
#print new_coordlist
return new_coordlist
def sort_coordlist(self, coordlist, word): # give each coordinate a score, then sort
new_coordlist = []
for coord in coordlist:
col, row, vertical = coord[0], coord[1], coord[2]
coord[4] = self.check_fit_score(col, row, vertical, word) # checking scores
if coord[4]: # 0 scores are filtered
new_coordlist.append(coord)
random.shuffle(new_coordlist) # randomize coord list; why not?
new_coordlist.sort(key=lambda i: i[4], reverse=True) # put the best scores first
return new_coordlist
def fit_and_add(self, word): # doesn't really check fit except for the first word; otherwise just adds if score is good
fit = False
count = 0
coordlist = self.suggest_coord(word)
while not fit and count < self.maxloops:
if len(self.current_word_list) == 0: # this is the first word: the seed
# top left seed of longest word yields best results (maybe override)
vertical, col, row = random.randrange(0, 2), 1, 1
'''
# optional center seed method, slower and less keyword placement
if vertical:
col = int(round((self.cols + 1)/2, 0))
row = int(round((self.rows + 1)/2, 0)) - int(round((word.length + 1)/2, 0))
else:
col = int(round((self.cols + 1)/2, 0)) - int(round((word.length + 1)/2, 0))
row = int(round((self.rows + 1)/2, 0))
# completely random seed method
col = random.randrange(1, self.cols + 1)
row = random.randrange(1, self.rows + 1)
'''
if self.check_fit_score(col, row, vertical, word):
fit = True
self.set_word(col, row, vertical, word, force=True)
else: # a subsquent words have scores calculated
try:
col, row, vertical = coordlist[count][0], coordlist[count][1], coordlist[count][2]
except IndexError: return # no more cordinates, stop trying to fit
if coordlist[count][4]: # already filtered these out, but double check
fit = True
self.set_word(col, row, vertical, word, force=True)
count += 1
return
def check_fit_score(self, col, row, vertical, word):
'''
And return score (0 signifies no fit). 1 means a fit, 2+ means a cross.
The more crosses the better.
'''
if col < 1 or row < 1:
return 0
count, score = 1, 1 # give score a standard value of 1, will override with 0 if collisions detected
for letter in word.word:
try:
active_cell = self.get_cell(col, row)
except IndexError:
return 0
if active_cell == self.empty or active_cell == letter:
pass
else:
return 0
if active_cell == letter:
score += 1
if vertical:
# check surroundings
if active_cell != letter: # don't check surroundings if cross point
if not self.check_if_cell_clear(col+1, row): # check right cell
return 0
if not self.check_if_cell_clear(col-1, row): # check left cell
return 0
if count == 1: # check top cell only on first letter
if not self.check_if_cell_clear(col, row-1):
return 0
if count == len(word.word): # check bottom cell only on last letter
if not self.check_if_cell_clear(col, row+1):
return 0
else: # else horizontal
# check surroundings
if active_cell != letter: # don't check surroundings if cross point
if not self.check_if_cell_clear(col, row-1): # check top cell
return 0
if not self.check_if_cell_clear(col, row+1): # check bottom cell
return 0
if count == 1: # check left cell only on first letter
if not self.check_if_cell_clear(col-1, row):
return 0
if count == len(word.word): # check right cell only on last letter
if not self.check_if_cell_clear(col+1, row):
return 0
if vertical: # progress to next letter and position
row += 1
else: # else horizontal
col += 1
count += 1
return score
def set_word(self, col, row, vertical, word, force=False): # also adds word to word list
if force:
word.col = col
word.row = row
word.vertical = vertical
self.current_word_list.append(word)
for letter in word.word:
self.set_cell(col, row, letter)
if vertical:
row += 1
else:
col += 1
return
def set_cell(self, col, row, value):
self.grid[row-1][col-1] = value
def get_cell(self, col, row):
return self.grid[row-1][col-1]
def check_if_cell_clear(self, col, row):
try:
cell = self.get_cell(col, row)
if cell == self.empty:
return True
except IndexError:
pass
return False
def solution(self): # return solution grid
outStr = ""
for r in range(self.rows):
for c in self.grid[r]:
outStr += '%s ' % c
outStr += '\n'
return outStr
def word_find(self): # return solution grid
outStr = ""
for r in range(self.rows):
for c in self.grid[r]:
if c == self.empty:
outStr += '%s ' % string.lowercase[random.randint(0,len(string.lowercase)-1)]
else:
outStr += '%s ' % c
outStr += '\n'
return outStr
def order_number_words(self): # orders words and applies numbering system to them
self.current_word_list.sort(key=lambda i: (i.col + i.row))
count, icount = 1, 1
for word in self.current_word_list:
word.number = count
if icount < len(self.current_word_list):
if word.col == self.current_word_list[icount].col and word.row == self.current_word_list[icount].row:
pass
else:
count += 1
icount += 1
def display(self, order=True): # return (and order/number wordlist) the grid minus the words adding the numbers
outStr = ""
if order:
self.order_number_words()
copy = self
for word in self.current_word_list:
copy.set_cell(word.col, word.row, word.number)
for r in range(copy.rows):
for c in copy.grid[r]:
outStr += '%s ' % c
outStr += '\n'
outStr = re.sub(r'[a-z]', ' ', outStr)
return outStr
def word_bank(self):
outStr = ''
temp_list = duplicate(self.current_word_list)
random.shuffle(temp_list) # randomize word list
for word in temp_list:
outStr += '%s\n' % word.word
return outStr
def legend(self): # must order first
outStr = ''
for word in self.current_word_list:
outStr += '%d. (%d,%d) %s: %s\n' % (word.number, word.col, word.row, word.down_across(), word.clue )
return outStr
class Word(object):
def __init__(self, word=None, clue=None):
self.word = re.sub(r'\s', '', word.lower())
self.clue = clue
self.length = len(self.word)
# the below are set when placed on board
self.row = None
self.col = None
self.vertical = None
self.number = None
def down_across(self): # return down or across
if self.vertical:
return 'down'
else:
return 'across'
def __repr__(self):
return self.word
### end class, start execution
#start_full = float(time.time())
word_list = ['saffron', 'The dried, orange yellow plant used to as dye and as a cooking spice.'], \
['pumpernickel', 'Dark, sour bread made from coarse ground rye.'], \
['leaven', 'An agent, such as yeast, that cause batter or dough to rise..'], \
['coda', 'Musical conclusion of a movement or composition.'], \
['paladin', 'A heroic champion or paragon of chivalry.'], \
['syncopation', 'Shifting the emphasis of a beat to the normally weak beat.'], \
['albatross', 'A large bird of the ocean having a hooked beek and long, narrow wings.'], \
['harp', 'Musical instrument with 46 or more open strings played by plucking.'], \
['piston', 'A solid cylinder or disk that fits snugly in a larger cylinder and moves under pressure as in an engine.'], \
['caramel', 'A smooth chery candy made from suger, butter, cream or milk with flavoring.'], \
['coral', 'A rock-like deposit of organism skeletons that make up reefs.'], \
['dawn', 'The time of each morning at which daylight begins.'], \
['pitch', 'A resin derived from the sap of various pine trees.'], \
['fjord', 'A long, narrow, deep inlet of the sea between steep slopes.'], \
['lip', 'Either of two fleshy folds surrounding the mouth.'], \
['lime', 'The egg-shaped citrus fruit having a green coloring and acidic juice.'], \
['mist', 'A mass of fine water droplets in the air near or in contact with the ground.'], \
['plague', 'A widespread affliction or calamity.'], \
['yarn', 'A strand of twisted threads or a long elaborate narrative.'], \
['snicker', 'A snide, slightly stifled laugh.']
a = Crossword(13, 13, '-', 5000, word_list)
a.compute_crossword(2)
print (a.word_bank())
print (a.solution())
print (a.word_find())
print (a.display())
print (a.legend())
print (len(a.current_word_list), 'out of', len(word_list))
print (a.debug)
resultat='/tmp/aa'
f=open(resultat,'w')
print (a.word_bank(),file=f)
print (a.solution(),file=f)
print (a.word_find(),file=f)
print (a.display(),file=f)
print (a.legend(),file=f)
print (len(a.current_word_list), 'out of', len(word_list),file=f)
print (a.debug,file=f)
#end_full = float(time.time())
#print end_full - start_full
f.close()
os.system('pluma '+resultat)
#Released under a BSD license. Copyright Bryan Helmig 2010.